Question on Cell emf

The Standard Reduction Potentials of Pb²⁺/Pb and Cu²⁺/Cu couples are -0.76V and +0.34V respectively. What will be the standard emf of the cell constructed with the two couples mentioned above?

Answer:

From the SRPs given in the question it could be found that, for the cell to be spontaneous Pb²⁺/Pb should act as the anode and Cu²⁺/Cu should act as the cathode. Also,

E^o_Cell = E^o_Cathode - E^o_Anode = 0.34 - (-0.76) = 0.34 + 0.76 = 1.1V