If the half life of a first order reaction is 120sec, how long would it take for the reaction to be 90% complete?
Answer:
The rate constant (k) = 0.693/120 = 5.775 * 10-2 sec-1
The time taken for 90% completion is
t = (2.303/5.775 * 10-2) * log (100/10) = 398.78 sec
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