When equal volumes of two solutions, one with pH = 2 and the other with pH = 1 are mixed, what will be the pH of the resulting solution?
Answer:
As both the solutions have the pH values as 1 and 2 we can conclude that they are acidic solutions. Let us call the solution with pH = 1 as A and that with pH = 2 as B.
The total H+ concentration from solution A is 10-1 and that from the solution B is 10-2.
Let 10mL of both the solutions be added (the actual volume does not make any difference in the pH of the final solution).
Millimoles of H+ from solution A = 10-1 * 100
Millimoles of H+ from solution B = 10-2 * 100
Total millimoles of H+ in the final solution is (10-1 * 100) + (10-2 * 100)
The total concentration of H+ in the final solution is ((10-1 * 100) + (10-2 * 100))/200 = 11/200 = 5.5 * 10-2 mol/L
So, the pH of the final solution is –log (5.5 * 10-2) = 2 – log5.5 = 1.26
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