When NaOH solution is added to an aqueous solution of Zinc Chloride, it produces a white precipitate which further dissolves on further addition of NaOH. Why?
Answer:
Zinc Chloride reacts with NaOH to produce a white precipitate of Zinc Hydroxide and on further addition to NaOH, forms a complex ion and hence dissoves.
ZnCl2 + 2NaOH = Zn(OH)2
Zn(OH)2 + 2NaOH = Na2[Zn(OH)4]
Zn(OH)2 is insoluble and Na2[Zn(OH)4] is soluble in water.
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