The following questions have appeared in JEE - Main / AIEEE. The Year in which the question appeared is mentioned after the question.
For each question 4 options are given out of which only one is correct.
The correct set of four quantum numbers for the valence electrons of Rubidium atom (z = 37) is:
A) \(5, 1, 1, +\dfrac{1}{2}\)
B) \(5, 0, 1, +\dfrac{1}{2}\)
C) \(5, 0, 0, +\dfrac{1}{2}\)
D) \(5, 1, 0, +\dfrac{1}{2}\)
[2014]
Energy of an electron is given by \(E = -2.178 \times 10^{-18} (\dfrac{Z^2}{n^2})J\). Wavelength of light required to excite an electron in an hydrogen atom from level n =1 to n = 2 will be
(\(h = 6.62 \times 10^{34}Js and c = 3.0 \times 10^8 m/s\))
A) \(2.816 \times 10^{-7}m\)
B) \(6.500 \times 10^{-7}m\)
C) \(8.500 \times 10^{-7}m\)
D) \(1.214 \times 10^{-7}m\)
[2013]
The electrons identified by quantum numbers n and l (1) n = 4, l = 1 (2) n = 4, l = 0 (3) n = 3, l = 2 (4) n = 4, l = 1 can be placed in the increasing order of energy as
A) (3) < (4) < (2) < (1)
B) (4) < (2) < (3) < (1)
C) (2) < (4) < (1) < (3)
D) (1) < (3) < (2) < (4)
[2012]
The frequency of light emitted for the transition n = 4 to n= 2 of \(He^+\) is equal to the transition in H atom corresponding to which of the following?
A) n = 4 to n= 3
B) n = 3 to n= 1
C) n = 2 to n= 1
D) n = 3 to n= 2
[2011]
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