Both 2-iodopentane and 3-iodopentane are formed as products when aqueous hydroiodic acid is treated with pent-2-ene. Which one of the two products is formed in major amounts?
Answer:
2-iodopentane is formed in major amounts because the carbocation intermediate leading to the formation of 2-iodopentane is more stable than that leading to 3-iodopentane.
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