What is the name of the Hydrocarbon with the molecular formula C4H8 that gives the same product on Markovnikov’s and anti-Markovnikov’s addition of aqueous HBr?
Answer:
Markovnikov’s Addition is that where the negative part of the addendum gets added to that carbon of the alkene having less number of hydrogen atoms (the one which is more substituted) and the reverse happens in anti-Markovnikov’s addition.
For a molecule to give the same product on both the modes of addition, it must be a symmetrical one. With the above argument and the molecular formula provided, the hydrocarbon should be but-2-ene.
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