How many grams of Calcium Chloride are formed when 1g each of Calcium and Chlorine are allowed to react completely?
Answer:
According to the following reaction 1 mole of Ca will react with 1 mole of Cl2.
Ca + Cl2 = CaCl2
1g of Ca is 1/40 moles and 1g of Cl2 is 1/71 moles. Cl2 is the limiting reagent in this reaction and will be completely consumed to produce 1/71 moles of CaCl2.
1/71 moles of CaCl2 is ((1/71) * 111)g = 1.56g
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